The Derivative of Sinh -1 x
Let y = sinh -1 x
We have no rules that will allow us to differentiate this function, so we are going to first write it into another form, so that we can apply differentiation rules that we have developed.
Apply the function sinh x to both sides of this equation, to obtain
sinh y = x
Rewrite this as,
x = sinh y
Now, we may rewrite the above function--using the exponential form of the hyperbolic sine function--as,

Multiply both sides of this equation by '2' and then flip the equation to obtain

Now, multiply both sides of this equation by
, so the equation becomes

and this may rewritten as
.
Now, we may seem to have created a mess, but we will soon be able to solve this equation for y and obtain a form that we can differentiate.
We now let z =
, so that the above equation turns into a quadratic equation in z
z2 - 2xz - 1 = 0.
We can solve this equation for z (using ? method) and obtain

which simplifies to
.
Now, since z =
(and
is always ? than 0), we may rewrite this as

(or the left side of this equation would be negative).
Now replace z with
and rewrite the above equation as

and the natural logarithmic function (ln x) to both sides of this equation to obtain,
.
We have now achieved our first goal of rewriting the function y = sinh -1x in a form which can be differentiated.
So, let's differentiate the above equation. We get

which simplifies to

and further simplifies to
.
We have now completed this derivation, as we now know that

which has the integral form
